Matematik A/Differentialregning: Forskelle mellem versioner

<math>(\frac{f(x)}{g(x)})^{\prime}=\frac{d(\frac{f(x)}{g(x)})}{dx}=\frac{f^{\prime}(x) \cdot g(x)-f(x) \cdot g^{\prime}(x)}{g(x)^2}</math>

 

 

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